Write a Palindrome Number Program in Python using While Loop, Functions, Recursion, lists, list comprehensions, and lambda expression code. We also print the list of palindrome numbers from 1 to N and 1 to 100. Any number could be Palindrome if it remained the same when we reversed it. For example, 131, 959, and 45654 because they remain the same after reversing them.
The common program approach to check for the Palindrome Number in Python is to reverse a given number. Compare the original value with the reverse value. If they exactly matched, then it is a Palindrome number. Otherwise, it is not.
In Python programming language, there are a wide array of approaches to reverse the digits in a number, including the iterative approach, functions, and recursive approach. In these programs, we can use the Python If Else statement to compare the original with the reverse and check or identify the palindrome number. Remember to preserve the original number by allocating it to the temporary value and reversing the temp value.
Python Palindrome Number Program using While Loop
This program allows the user to enter any integer value. Next, this Python program code uses While Loop to check whether a given number is Palindrome or Not.
# using While Loop
number = int(input("Please Enter any Value: "))
reverse = 0
temp = number
while(temp > 0):
Reminder = temp % 10
reverse = (reverse * 10) + Reminder
temp = temp //10
print("Reverse of it is = %d" %reverse)
if(number == reverse):
print("%d is a Palindrome" %number)
else:
print("%d is Not" %number)
User Entered values in this palindrome program in Python code are Number = 191 and Reverse = 0
Temp = Number
Temp = 191
While Loop First Iteration
Reminder = Temp %10
Reminder = 191 % 10 = 1
Reverse = Reverse *10 + Reminder => 0 * 10 + 1 = 1
Temp = Temp //10 = 191 /10
Temp = 19
Second Iteration: From the first while loop Iteration, the values changed as Temp = 19 and Reverse = 1
Reminder = 19 % 10 = 9
Reverse = 1 * 10 + 9 = 19
Temp = 19 /10 = 1
Third Iteration: From the Second Iteration of the program, the values of Temp = 1 and Reverse = 19
Reminder = 1 % 10 = 1
Reverse = 19 * 10 + 1 = 191
Temp = 1/10
Temp = 0
Here Num = 0. So, the Python while loop condition fails.
if ( Number == Reverse ) – condition checks whether the user entered number is exactly equal to the Reverse or not. If this condition is True, then it is. Else it is not.
Python Program to Check Palindrome Number using for loop
This program is the same as the while loop. However, the for loop iterates the number by converting it to a string.
num = int(input("Enter any Value: "))
rev = 0
temp = num
for _ in range(len(str(num))):
rem = num % 10
rev = (rev * 10) + rem
num //= 10
if temp == rev:
print('Palindrome')
else:
print("Not")
Python Program for Palindrome Number using string slice code
In this program, str(num) converts the user-entered number to a string and [::-1] slices or reverses the string. Next, int(str(num)[::-1]) will convert the reserved string to a number.
n = int(input("Enter any Value: "))
rev = int(str(n)[::-1])
if n == rev:
print('Palindrome')
else:
print("Not")
Enter any Value: 145541
PalindromeAlternatively, you can compare the strings. First, convert the number to a string and then compare it with the reverse of it.
num = int(input("Enter any Value: "))
strNum = str(num)
if strNum == strNum[::-1]:
print('Palindrome')
else:
print("Not")
Enter any Value: 1243
Not
Enter any Value: 19791
PalindromePython Program to Check Palindrome Number Using Functions
In this program, we defined an isPalindrome function. Within that function, we used the while loop. Next, the If Else statement to check the actual equal inverse.
# using Functions
def isPalindrome(val):
inverse = 0
while(val > 0):
Remi = val % 10
inverse = (inverse * 10) + Remi
val = val // 10
return inverse
val = int(input("Please Enter any Num: "))
rev = isPalindrome(val)
print("Inverse = %d" %rev)
if(val == rev):
print("%d is a Palindrome" %val)
else:
print("%d is not" %val)
Please Enter any Num: 1441
Inverse = 1441
1441 is a Palindrome
Please Enter any Num: 1202
Inverse = 2021
1202 is notPython Program to Check Palindrome Number using Recursion
In this Python program code, we check whether a given number is Palindrome or Not using the Recursive Functions concept.
# using Recursive Functions
rev = 0
def isPalindrome(num):
global rev
if(num > 0):
Reminder = num % 10
rev = (rev * 10) + Reminder
isPalindrome(num // 10)
return rev
num = int(input("Please Enter any Num: "))
rev = isPalindrome(num)
print("Reverse = %d" %rev)
if(num == rev):
print("%d is a Palindrome" %num)
else:
print("%d is not" %num)
In this program, within the checks using recursion function declaration,
integer_rev (Num//10) – it helps to call the function Recursively with the updated value. If you miss this statement, it terminates after completing the first line. For example, Num = 191, then the output is 1
Let’s see the If condition.
if (num > 0) check whether it is greater than 0 or not. For Recursive functions, placing a condition before using the function recursively is very important. Otherwise, we end up in infinite execution (Same as an infinite Loop).
Python Palindrome Number program using Lists
This example creates an empty list. And for each iteration, it appends the last digit to a list.
num = int(input("Please Enter any Value: "))
numList = []
temp = num
while temp > 0:
numList.append(temp % 10)
temp //= 10
reverse = numList[::-1]
if num == reverse:
print(num, " is a Palindrome.")
else:
print(num, "is Not.")
Enter any Value: 19791
PalindromeProgram for Palindrome Number in Python using List Comprehension
This program uses list comprehension.
- str(num) – The str() function converts the num integer to a string.
- [int(i) for i in str(num)] – The list comprehension reads each individual digit and creates a list of those digits. Here, int(i) converts each character back to a digit.
- digits[::-1] – It reverses the list using the slicing technique. You can also try the list reverse function.
- The if statement checks whether each digit equals the reverse of it.
num = int(input("Enter any Num: "))
digits = [int(i) for i in str(num)]
if digits == digits[::-1]:
print('Palindrome')
else:
print("Not")
Please Enter any Num: 112211
PalindromePython Program to Check Palindrome Number using lambda function
This code uses the lambda expression and str() function.
num = int(input("Enter any Value: "))
isPalindrome = lambda num: str(num) == str(num)[::-1]
if isPalindrome(num):
print('Palindrome')
else:
print("Not")
Enter any Value: 1971
NotPython program to print Palindrome Numbers from 1 to N
This section explains how to write a Python Program to print Palindrome numbers from 1 to 100 or 1 to n or minimum to maximum with an example.
This program allows you to enter the maximum value and prints the palindrome numbers from 1 to that number.
maximum = int(input(" Please Enter the Maximum Value : "))
print("Between 1 and %d are : " %maximum)
for num in range(1, maximum + 1):
temp = num
rv = 0
while(temp > 0):
Reminder = temp % 10
rv = (rv * 10) + Reminder
temp = temp //10
if(num == rv):
print("%d " %num, end = ' ')
Please Enter the Maximum Value : 4554
Between 1 and 4554 are :
1 2 3 4 5 6 7 8 9 11 22 33 44 55 66 77 88 99 101 111 121 131 141 151 161 171 181 191 202 212 222 232 242 252 262 272 282 292 303 313 323 333 343 353 363 373 383 393 404 414 424 434 444 454 464 474 484 494 505 515 525 535 545 555 565 575 585 595 606 616 626 636 646 656 666 676 686 696 707 717 727 737 747 757 767 777 787 797 808 818 828 838 848 858 868 878 888 898 909 919 929 939 949 959 969 979 989 999 1001 1111 1221 1331 1441 1551 1661 1771 1881 1991 2002 2112 2222 2332 2442 2552 2662 2772 2882 2992 3003 3113 3223 3333 3443 3553 3663 3773 3883 3993 4004 4114 4224 4334 4444 4554 Python Program to print Palindrome numbers from 1 to 100 using While Loop
This Python program allows the user to enter the maximum limit value. Next, this program prints palindrome numbers from 1 to the user-entered value. First, we used For Loop to iterate a loop between 1 and the maximum value. within the for loop,
- We used While Loop to reverse the given number.
- The if statement checks whether the given number is Palindrome Number or Not. For this, it compares the original value with the reverse number.
TIP: I suggest you refer to the Reverse a Number article to understand this Python program logic.
maximum = int(input(" Please Enter the Maximum Value : "))
print("Palindrome Numbers between 1 and %d are : " %(maximum))
for num in range(1, maximum + 1):
temp = num
reverse = 0
while(temp > 0):
Reminder = temp % 10
reverse = (reverse * 10) + Reminder
temp = temp //10
if(num == reverse):
print("%d " %num, end = ' ')
Palindrome numbers from 1 to 1000 output
Please Enter the Maximum Value : 1000
Palindrome Numbers between 1 and 1000 are :
1 2 3 4 5 6 7 8 9 11 22 33 44 55 66 77 88 99 101 111 121 131 141 151 161 171 181 191 202 212 222 232 242 252 262 272 282 292 303 313 323 333 343 353 363 373 383 393 404 414 424 434 444 454 464 474 484 494 505 515 525 535 545 555 565 575 585 595 606 616 626 636 646 656 666 676 686 696 707 717 727 737 747 757 767 777 787 797 808 818 828 838 848 858 868 878 888 898 909 919 929 939 949 959 969 979 989 999 Python Program to Display Palindrome Numbers from 1 to N Using Functions
In this Python program, we allow users to enter the minimum and maximum values. Next, it prints palindrome numbers between the minimum and maximum values.
minimum = int(input(" Please Enter the Minimum Value : "))
maximum = int(input(" Please Enter the Maximum Value : "))
print("Palindrome Numbers between %d and %d are : " %(minimum, maximum))
for num in range(minimum, maximum + 1):
temp = num
reverse = 0
while(temp > 0):
Reminder = temp % 10
reverse = (reverse * 10) + Reminder
temp = temp //10
if(num == reverse):
print("%d " %num, end = ' ')
