Python Program to Sort List in Ascending Order

In this article, we will show you, How to write a Python Program to Sort List in Ascending Order with practical example. Before you start, please refer List article to understand everything about Lists.

Python Program to Sort List in Ascending Order

This python program will allow a user to enter any integer value. This is a length of a List. Next, we used For Loop to add numbers to the list.

TIP: Python Sort function will sort the List in Ascending Order

# Python Program to Sort List in Ascending Order

NumList = []

Number = int(input("Please enter the Total Number of List Elements: "))
for i in range(1, Number + 1):
    value = int(input("Please enter the Value of %d Element : " %i))
    NumList.append(value)

NumList.sort()

print("Element After Sorting List in Ascending Order is : ", NumList)

OUTPUT

Python Program to Sort List in Ascending Order without using Sort

In this program, we are using Nested For Loop to iterate each and every number in a List, and sort them in ascending order.

# Python Program to Sort List in Ascending Order

NumList = []

Number = int(input("Please enter the Total Number of List Elements: "))
for i in range(1, Number + 1):
    value = int(input("Please enter the Value of %d Element : " %i))
    NumList.append(value)

for i in range (Number):
    for j in range(i + 1, Number):
        if(NumList[i] > NumList[j]):
            temp = NumList[i]
            NumList[i] = NumList[j]
            NumList[j] = temp

print("Element After Sorting List in Ascending Order is : ", NumList)

OUTPUT

ANALYSIS

First For Loop – First Iteration: for 0 in range(0, 4)
The condition is True so, it will enter into second for loop

Nested For Loop – First Iteration: for 1 in range(0 + 1, 4)
Condition is True so, compiler will enter into the If Statement

if(NumList[0] > NumList[1]) = if(67 > 86)
It means, Condition is False. So, it will exit from If block, and j value will be incremented by 1.

Nested For Loop – Second Iteration: for 2 in range(1, 4) – Condition is True
if(67 > 34) – Condition is True
temp = 67
NumList[i] = 34
NumList[j] = 67
Now the List will be 34 86 67 55. Next, j will be increment by 1.

Nested For Loop – Third Iteration: for 3 in range(1, 4) – Condition is True
if(34 > 55) – Condition is False. So, compiler exit from the If block, and j value will be 4.

Nested For Loop – Fourth Iteration: for 4 in range(1, 4) – Condition is False
Next, i value will be incremented by 1.

First For Loop – Second Iteration: for 1 in range(0, 4)
The condition is True so, it will enter into second for loop

Do the same for the remaining Iterations

Python Program to Sort List in Ascending Order using While Loop

This program is same as above. However, we replaced For Loop with While loop.

# Python Program to Sort List in Ascending Order

NumList = []

Number = int(input("Please enter the Total Number of List Elements: "))
for i in range(1, Number + 1):
    value = int(input("Please enter the Value of %d Element : " %i))
    NumList.append(value)

i = 0
while(i < Number):
    j = i + 1
    while(j < Number):
        if(NumList[i] > NumList[j]):
            temp = NumList[i]
            NumList[i] = NumList[j]
            NumList[j] = temp
        j = j + 1
    i = i + 1

print("Element After Sorting List in Ascending Order is : ", NumList)

OUTPUT