Python Program to find roots of a Quadratic Equation

In this article, we will show you, How to write a Python program to find Roots of a Quadratic Equation with example.

The mathematical representation of a Quadratic Equation is ax²+bx+c = 0. A Quadratic Equation can have two root and they are completely depends upon the discriminant

If discriminant > 0 then Two Distinct Real Roots will exists for this equation

If discriminant = 0, Two Equal and Real Roots will exists

and if discriminant < 0, Two Distinct Complex Roots will exists

Python Program to find roots of a Quadratic Equation using elif

This python program allows user to enter three values for a, b, and c. Using those values, this program will find roots of a quadratic equation using Elif Statement.

# Python Program to find roots of a Quadratic Equation
import math

a = int(input("Please Enter a Value of a Quadratic Equation : "))
b = int(input("Please Enter b Value of a Quadratic Equation : "))
c = int(input("Please Enter c Value of a Quadratic Equation : "))

discriminant = (b * b) - (4 * a * c)

if(discriminant > 0):
    root1 = (-b + math.sqrt(discriminant) / (2 * a))
    root2 = (-b - math.sqrt(discriminant) / (2 * a))
    print("Two Distinct Real Roots Exists: root1 = %.2f and root2 = %.2f" %(root1, root2))
elif(discriminant == 0):
    root1 = root2 = -b / (2 * a)
    print("Two Equal and Real Roots Exists: root1 = %.2f and root2 = %.2f" %(root1, root2))
elif(discriminant < 0):
    root1 = root2 = -b / (2 * a)
    imaginary = math.sqrt(-discriminant) / (2 * a)
    print("Two Distinct Complex Roots Exists: root1 = %.2f+%.2f and root2 = %.2f-%.2f" %(root1, imaginary, root2, imaginary))

OUTPUT