Write a Python program to check a number is a disarium number or not using a while loop. If the sum of the digits of a given number raised to the power of its respective positions equals the actual number, it is a disarium number. For instance, 175 = 11 + 72 + 53 = 1 + 49 + 125 = 175.
In this Python program, we divide the number into individual digits and find the sum. Next, the if statement checks whether the sum equals an actual number. If True, it is a disarium number.
Number = int(input("Enter the Number to Check Disarium Number = ")) length = len(str(Number)) Temp = Number Sum = 0 rem = 0 while Temp > 0: rem = Temp % 10 Sum = Sum + int(rem**length) Temp = Temp // 10 length = length - 1 print("The Sum of the Digits = %d" %Sum) if Sum == Number: print("\n%d is a Disarium Number." %Number) else: print("%d is Not a Disarium Number." %Number)

In this Python example, we used the digitsCount and digitsSum to check whether the number is a disarium number or not.
import math def digitsCount(Number): length = 0 while Number != 0: length = length + 1 Number = Number // 10 return length def digitsSum(Number, length): Sum = 0 rem = 0 while Number > 0: rem = Number % 10 Sum = Sum + math.pow(rem, length) Number = Number // 10 length = length - 1 return Sum Number = int(input("Enter the Number to Check Disarium Number = ")) length = digitsCount(Number) Sum = digitsSum(Number, length) print("The Sum of the Digits = %d" %Sum) if Sum == Number: print("%d is a Disarium Number." %Number) else: print("%d is Not a Disarium Number." %Number)
Enter the Number to Check Disarium Number = 175
The Sum of the Digits = 175
175 is a Disarium Number.
Enter the Number to Check Disarium Number = 24
The Sum of the Digits = 18
24 is Not a Disarium Number.
Python program to check a number is a disarium number or not using recursion.
import math length = 0 Sum = 0 def digitsCount(Number): global length if Number > 0: length = length + 1 digitsCount(Number // 10) return length def digitsSum(Number, length): global Sum if Number > 0: rem = Number % 10 Sum = Sum + math.pow(rem, length) digitsSum(Number // 10, length = length - 1) return Sum Number = int(input("Enter the Number to Check Disarium Number = ")) length = digitsCount(Number) Sum = digitsSum(Number, length) print("The Sum of the Digits = %d" %Sum) if Sum == Number: print("\n%d is a Disarium Number." %Number) else: print("%d is Not a Disarium Number." %Number)
Enter the Number to Check Disarium Number = 98
The Sum of the Digits = 73
98 is Not a Disarium Number.
Enter the Number to Check Disarium Number = 135
The Sum of the Digits = 135
135 is a Disarium Number.