# Java Program to Calculate Sum of Even Numbers

Write a Java Program to Calculate Sum of Even Numbers from 1 to N using For Loop, and While Loop with example. Any number that is divisible by 2 is an even number.

## Java Program to Calculate Sum of Even Numbers Example 1

This Java program allows the user to enter the maximum limit value. Next, this Java program finds the sum of even numbers from 1 to maximum limit value using For Loop and If statement.

TIP : We already explained the logic to check the number is Even or Not in Java Odd or Even Program article in Java.

```// Java Program to Calculate Sum of Even Numbers using for loop
import java.util.Scanner;

public class SumofEven1 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

for(i = 1; i <= number; i++)
{
if(i % 2 == 0)
{
evenSum = evenSum + i;
}
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```

First, we used the For loop to iterate from 1 to maximum value (Here, number = 5). Next, the If condition to check whether the remainder of the number divided by 2 is exactly equal to 0 or not.

User entered value for this Java Program to find Sum of Even Numbers : number  = 5

For Loop First Iteration: for(i = 1; i <= 5; i++)
if(i % 2 == 0) => if(1 % 2 == 0) – Condition is False

Second Iteration: for(i = 2; 2 <= 5; 2++)
if(2 % 2 == 0) – Condition is True.
evenSum = evenSum + i
evenSum = 0 + 2 = 2

Third Iteration: for(i = 3; 3 <= 5; 3++)
if(3 % 2 == 0) – False

Fourth Iteration: for(i = 4; 4 <= 5; 4++)
if(4 % 2 == 0) – True.
evenSum = evenSum + i
evenSum = 2 + 4 = 6

Fifth Iteration: for(i = 5; 5 <= 5; 5++)
if(5 % 2 == 0) – False

Sixth Iteration: for(i = 6; 6 <= 5; 6++)
Condition (6 <= 5) is False. So, the Java compiler exits from the For Loop

## Java Program to Calculate Sum of Even Numbers Example 2

In this Java program, we used for loop without the If statement. If you observe the below Java code, we started i from 2 and incremented by 2 (not 1). It means, for the first iteration i = 2, and for the second iteration i = 4 (not 3) so on.

```// Java Program to Calculate Sum of Even Numbers
import java.util.Scanner;

public class SumofEven2 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

for(i = 2; i <= number; i = i + 2)
{
evenSum = evenSum + i;
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```

Java Sum of Even Numbers using for loop output

`````` Please Enter any Number : 25

The Sum of Even Numbers upto 25  =  156``````

## Java Program to Calculate Sum of Even Numbers Example 3

This Java program to find the sum of even numbers is the same as the second example, but we are using the While Loop.

```// Java Program to find Sum of Even Numbers using While Loop
import java.util.Scanner;

public class SumofEven5 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i = 2, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

while(i <= number)
{
evenSum = evenSum + i;
i = i + 2;
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```
`````` Please Enter any Number : 35

The Sum of Even Numbers upto 35  =  306``````

## Java Program to Calculate Sum of Even Numbers using Method

This program is the same as the first example. But we separated the logic and placed it in a separate method.

```// Java Program to find Sum of Even Numbers
import java.util.Scanner;

public class SumofEven3 {
private static Scanner sc;
public static void main(String[] args)
{
int number, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

evenSum = sumOfEven(number);

System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
public static int sumOfEven(int num)
{
int i, sum = 0;
for(i = 1; i <= num; i++)
{
if(i % 2 == 0)
{
sum = sum + i;
}
}
return sum;
}
}```
`````` Please Enter any Number : 45

The Sum of Even Numbers upto 45  =  506``````

## Java Program to find Sum of Even Numbers between a Given Range

This Java program allows the user to enter Minimum and maximum value. Next, the Java program calculates the sum of even numbers between Minimum value and maximum value.

```// Java Program to Calculate Sum of Even Numbers between Maximum and Minimum
import java.util.Scanner;

public class SumofEven4 {
private static Scanner sc;
public static void main(String[] args)
{
int minimum, maximum, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter the Minimum value : ");
minimum = sc.nextInt();

System.out.print(" Please Enter the Maximum value : ");
maximum = sc.nextInt();

evenSum = sumOfEven(minimum, maximum);
System.out.println("\n The Sum of Even Numbers from " + minimum + " to " + maximum + "  =  " + evenSum);
}

public static int sumOfEven(int minimum, int maximum)
{
int i, sum = 0;
if(minimum % 2 != 0)
{
minimum++;
}
for(i = minimum; i <= maximum; i++)
{
if(i % 2 == 0)
{
sum = sum + i;
}
}
return sum;
}
}```
`````` Please Enter the Minimum value : 10
Please Enter the Maximum value : 75

The Sum of Even Numbers from 10 to 75  =  1386``````