# Java Program to Calculate Sum of Even Numbers

Write a Java Program to Calculate Sum of Even Numbers from 1 to N using For Loop, and While Loop with example. Any number that is divisible by 2 is an even number.

## Java Program to Calculate Sum of Even Numbers Example 1

This Java program allows the user to enter the maximum limit value. Next, this Java program finds the sum of even numbers from 1 to maximum limit value using For Loop and If statement.

TIP : We already explained the logic to check the number is Even or Not in Java Odd or Even Program article in Java.

```// Java Program to Calculate Sum of Even Numbers using for loop
import java.util.Scanner;

public class SumofEven1 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

for(i = 1; i <= number; i++)
{
if(i % 2 == 0)
{
evenSum = evenSum + i;
}
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```

First, we used the For loop to iterate from 1 to maximum value (Here, number = 5). Next, the If condition to check whether the remainder of the number divided by 2 is exactly equal to 0 or not.

User entered value for this Java Program to find Sum of Even Numbers : number  = 5

For Loop First Iteration: for(i = 1; i <= 5; i++)
if(i % 2 == 0) => if(1 % 2 == 0) – Condition is False

Second Iteration: for(i = 2; 2 <= 5; 2++)
if(2 % 2 == 0) – Condition is True.
evenSum = evenSum + i
evenSum = 0 + 2 = 2

Third Iteration: for(i = 3; 3 <= 5; 3++)
if(3 % 2 == 0) – False

Fourth Iteration: for(i = 4; 4 <= 5; 4++)
if(4 % 2 == 0) – True.
evenSum = evenSum + i
evenSum = 2 + 4 = 6

Fifth Iteration: for(i = 5; 5 <= 5; 5++)
if(5 % 2 == 0) – False

Sixth Iteration: for(i = 6; 6 <= 5; 6++)
Condition (6 <= 5) is False. So, the Java compiler exits from the For Loop

## Java Program to Calculate Sum of Even Numbers Example 2

In this Java program, we used for loop without the If statement. If you observe the below Java code, we started i from 2 and incremented by 2 (not 1). It means, for the first iteration i = 2, and for the second iteration i = 4 (not 3) so on.

```// Java Program to Calculate Sum of Even Numbers
import java.util.Scanner;

public class SumofEven2 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

for(i = 2; i <= number; i = i + 2)
{
evenSum = evenSum + i;
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```

Java Sum of Even Numbers using for loop output

`````` Please Enter any Number : 25

The Sum of Even Numbers upto 25  =  156``````

## Java Program to Calculate Sum of Even Numbers Example 3

This Java program to find the sum of even numbers is the same as the second example, but we are using the While Loop.

```// Java Program to find Sum of Even Numbers using While Loop
import java.util.Scanner;

public class SumofEven5 {
private static Scanner sc;
public static void main(String[] args)
{
int number, i = 2, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

while(i <= number)
{
evenSum = evenSum + i;
i = i + 2;
}
System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
}```
`````` Please Enter any Number : 35

The Sum of Even Numbers upto 35  =  306``````

## Java Program to Calculate Sum of Even Numbers using Method

This program is the same as the first example. But we separated the logic and placed it in a separate method.

```// Java Program to find Sum of Even Numbers
import java.util.Scanner;

public class SumofEven3 {
private static Scanner sc;
public static void main(String[] args)
{
int number, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter any Number : ");
number = sc.nextInt();

evenSum = sumOfEven(number);

System.out.println("\n The Sum of Even Numbers upto " + number + "  =  " + evenSum);
}
public static int sumOfEven(int num)
{
int i, sum = 0;
for(i = 1; i <= num; i++)
{
if(i % 2 == 0)
{
sum = sum + i;
}
}
return sum;
}
}```
`````` Please Enter any Number : 45

The Sum of Even Numbers upto 45  =  506``````

## Java Program to find Sum of Even Numbers between a Given Range

This Java program allows the user to enter Minimum and maximum value. Next, the Java program calculates the sum of even numbers between Minimum value and maximum value.

```// Java Program to Calculate Sum of Even Numbers between Maximum and Minimum
import java.util.Scanner;

public class SumofEven4 {
private static Scanner sc;
public static void main(String[] args)
{
int minimum, maximum, evenSum = 0;
sc = new Scanner(System.in);

System.out.print(" Please Enter the Minimum value : ");
minimum = sc.nextInt();

System.out.print(" Please Enter the Maximum value : ");
maximum = sc.nextInt();

evenSum = sumOfEven(minimum, maximum);
System.out.println("\n The Sum of Even Numbers from " + minimum + " to " + maximum + "  =  " + evenSum);
}

public static int sumOfEven(int minimum, int maximum)
{
int i, sum = 0;
if(minimum % 2 != 0)
{
minimum++;
}
for(i = minimum; i <= maximum; i++)
{
if(i % 2 == 0)
{
sum = sum + i;
}
}
return sum;
}
}```
`````` Please Enter the Minimum value : 10
Please Enter the Maximum value : 75

The Sum of Even Numbers from 10 to 75  =  1386`````` Suresh is the founder of TutorialGateway and a freelance software developer. He specialized in Designing and Developing Windows and Web applications. The experience he gained in Programming and BI integration, and reporting tools translates into this blog. You can find him on Facebook or Twitter.