Java Odd Even Program

If the given number is divisible by 2 then we called it as even number and remaining ones (not divisible by 2) are called as odd numbers. In this article we will write Java Odd Even Program to show you, How to check whether the given number is Odd or Even number using If Statement and Conditional Operator with example

In Java Programming, we have an % (Module) Arithmetic Operator to check the remainder. Let’s use this operator to check the remainder, if the remainder is 0 then the number is even otherwise odd number.

Java Odd Even Program using IF Condition

This Java program allows the user to enter any integer value and checks whether that number is even or odd using Java If statement.

//Java Odd Even Program using If Else Statement
package SimpleNumberPrograms;

import java.util.Scanner;

public class EvenorOddUsingIf {
	private static Scanner sc;
	
	public static void main(String[] args) {
		int Number;
		sc = new Scanner(System.in);		
		System.out.println("\n Please Enter any integer Value: ");
		Number = sc.nextInt();
		
		if (Number % 2 == 0) {
			System.out.println("\n You have entered EVEN Number");
		}
		else {
			System.out.println("\n You have entered ODD Number");
		}
	}
}

ANALYSIS

Within the Java even or odd example, the following statement will ask the user to Enter any integer value to check whether it is Even or Odd.

System.out.println("\n Please Enter any integer Value: ");

Below statement will assign the user entered value to number variable.

Number = sc.nextInt();

In the Next line, We declared the If Else statement to check even or odd in Java

if (Number % 2 == 0) {

As we all know, number that is completely divisible by 2 is even number. So, we used the If condition to check whether the remainder of the number divided by 2 is exactly equal to 0 or not.

If the condition is True then the statement inside the If block will be printed. That is Even number
If the condition is False the statement inside the Else block will be printed. That is Odd number

OUTPUT

We have entered the value as 48 to check and it is returning the even number as output

Java Odd Even Program using Conditional Operator

This Java program allows the user to enter any integer value and checks whether that number is even or odd using the Java Ternary operator. Lets see the example

//Java Odd Even Program using Conditional Operator
package SimpleNumberPrograms;

import java.util.Scanner;

public class EvenorOddUsingConditional {
 private static Scanner sc;
 
 public static void main(String[] args) {
 int Number;
 sc = new Scanner(System.in); 
 System.out.println("\n Please Enter the First integer Value: ");
 Number = sc.nextInt();
 
 System.out.println((Number%2)==0? "\n You have entered EVEN Number":
                 "\n You have entered ODD Number");
 }
}

OUTPUT

From the below screenshot you can observe that, we entered 19 as input. As you can see it is returning Odd Number as Output

Java Odd Even Program using Conditional Operator

You can observe from the above code that, we used if condition to check whether the remainder of the given integer divisible by 2 is 0 or not and print as per the result.

Let us enter 28 to check the other output

Java Odd Even Program using Conditional Operator 2

Java Odd Even Program using Methods

In this Java program we are using the same steps that we followed in our first example. However, in this Java program, we separated the logic to find even or odd and placed in the separate method.

package SimpleNumberPrograms;

import java.util.Scanner;

public class EvenorOddUsingMethods {

	private static Scanner sc;
	
	public static void main(String[] args) {
		int Number;
		sc = new Scanner(System.in);		
		System.out.println("\n Please Enter the First integer Value: ");
		Number = sc.nextInt();
		
		evenOrOdd(Number);

	}	
	public static void evenOrOdd(int Number) {
		if (Number % 2 == 0) {
			System.out.println("\n You have entered EVEN Number");
		}
		else {
			System.out.println("\n You have entered ODD Number");
		}
	}
}

OUTPUT

ANALYSIS

If you observe the following statement, we are calling the evenOrOdd method

evenOrOdd(Number);

Let us see the code inside the evenOrOdd method

public static void evenOrOdd(int Number) {
	if (Number % 2 == 0) {
		System.out.println("\n You have entered EVEN Number");
	}
	else {
		System.out.println("\n You have entered ODD Number");
	}
}

From the above code snippet, you can observe that, this method accepts one arguments of integer type. Within the function we are performing the same operation that we explained in our previous example.

Java Odd Even Program using OOPs

In this program, we are dividing the code using the Object Oriented Programming. To do this, First we will create a class which holds two methods.

TIP: In general, You don’t have to write first method. We used this method to show the available options

package SimpleNumberPrograms;

public class EvenOrOdd {
	int x;
	
	public void evenOrOdd() {
		if (x % 2 == 0) {
			System.out.println("\n First Method: You have entered EVEN Number");
		}
		else {
			System.out.println("\n First Method: You have entered ODD Number");
		}
	}	
	public int evenOrOddAgain(int Number) {
		if (Number % 2 == 0) {
			return 1;
		}
		else {
			return 0;
		}
	}
}

Within the Main program, we will create an instance of the above specified class and call the methods to find even or odd in Java

package SimpleNumberPrograms;

import java.util.Scanner;

public class EvenorOddUsingClass {
 private static Scanner sc;
 public static void main(String[] args) {
 int Number;
 sc = new Scanner(System.in); 
 System.out.println("\nPlease Enter the integer Value to check Even or Odd: ");
 Number = sc.nextInt();
 
 EvenOrOdd eo = new EvenOrOdd();
 eo.x = Number;
 
 eo.evenOrOdd();
 if (eo.evenOrOddAgain(Number) != 0) {
 System.out.println("\n Second Method: You have entered EVEN Number");
 }
 else {
 System.out.println("\n Second Method: You have entered ODD Number");
 }
 }
}

OUTPUT

ANALYSIS

EvenOrOdd Class Analysis:

First we declared a function evenOrOdd with zero arguments. Within the function, we used If statement to check whether the given number is perfectly divisible by 2 or not. If it is True, we are printing Even Number statement otherwise, Odd Number statement using System.out.println statement.
Next we declared an integer function evenOrOddAgain with one arguments. Within the function, we used If statement to check whether the given number is perfectly divisible by 2 or not. If it is True, we are returning Value 1 otherwise, 0.

TIP: If you declare a method with void keyword then we can’t return any value. If you want to return any value then replace void with data type and add return keyword.

Main Class Analysis:

First we created an instance / created an Object of the EvenOrOdd Class

EvenOrOdd eo = new EvenOrOdd();

Next, we are assigning the user entered values to the EvenOrOdd Class variables.

eo.x = Number;

Next, we are calling the evenOrOdd method. Note, this is the first method that we created with void keyword and this method will check for even or odd and print the output from the EvenOrOdd Class itself.

eo.evenOrOdd();

Next, Within the If statement we are calling the evenOrOddAgain method and checking whether the return value is Not Equal to Zero or Not. If the condition is True statement inside the If block will be executed otherwise, it will execute the statement inside the else block