Java Program to Print Odd Numbers from 1 to N

How to write a Java Program to Print Odd Numbers from 1 to N using For Loop, While Loop with an example. If the given number is not divisible by 2, it is an odd number.

Java Program to Print Odd Numbers from 1 to N Example 1

This Java program allows entering the maximum limit value. Next, this program prints the odd numbers from 1 to the maximum limit value using For Loop and If statements.

In Java, we have a % Arithmetic Operator to check the remainder. If the remainder is not 0, the number is odd.

import java.util.Scanner;

public class OddNumbers1 {
	private static Scanner sc;
	public static void main(String[] args) 
	{
		int number, i;
		sc = new Scanner(System.in);
		
		System.out.print(" Please Enter any Number : ");
		number = sc.nextInt();	
		
		for(i = 1; i <= number; i++)
		{
			if(i % 2 != 0)
			{
				System.out.print(i +"\t"); 
			}
		}	
	}
}

Java Program to Print Odd Numbers from 1 to N 1

The for loop iterates from 1 to the maximum value (Here, number = 5). And we know that if the number is not divisible by 2, it is an odd number. So, we used the Java If condition to check the remainder.

User entered value: number = 5

For Loop First Iteration: for(i = 1; i <= 5; i++)
if(i % 2 != 0) => if(1 % 2 != 0)
Condition is True. So, i value printed

Second Iteration: for(i = 2; 2 <= 5; 2++)
if(2 % 2 != 0) – Condition is False.

Third Iteration: for(i = 3; 3 <= 5; 3++)
if(3 % 2 != 0) – the For Loop Condition is True. So, i value printed

Fourth Iteration: for(i = 4; 4 <= 5; 4++)
if(4 % 2 != 0) – Condition is False.

Fifth Iteration: for(i = 5; 5 <= 5; 5++)
if(5 % 2 != 0) – Condition is True. So, it prints i

Sixth Iteration: for(i = 6; 6 <= 5; 6++)
Condition (6 <= 5) is False. So, the Java compiler exits from the For Loop

Java Program to Print Odd Numbers from 1 to N Example 2

This program to display odd numbers from 1 to N is the same as above, but we altered the for loop to eliminate the If statement. If you observe the Java code, we started i from 1 and incremented by 2 (not 1). It means for the first iteration i = 1, and for the second iteration i = 3 (not 2) so on.

import java.util.Scanner;

public class OddNumbers2 {
	private static Scanner sc;
	public static void main(String[] args) 
	{
		int number, i;
		sc = new Scanner(System.in);
		
		System.out.print(" Please Enter any Number : ");
		number = sc.nextInt();	
		
		for(i = 1; i <= number; i = i + 2)
		{
			System.out.print(i +"\t"); 
		}	
	}
}

Please Enter any Number : 20
1	3	5	7	9	11	13	15	17	19

Java Program to Print Odd Numbers from 1 to N Example 3

This program to return odd numbers from 1 to 100 is the same as the second example, but we used While Loop.

import java.util.Scanner;

public class OddNumbers3 {
	private static Scanner sc;
	public static void main(String[] args) 
	{
		int number, i;
		sc = new Scanner(System.in);
		
		System.out.print(" Please Enter any Number : ");
		number = sc.nextInt();	
		i = 1; 
		
		while(i <= number)
		{
			System.out.print(i +"\t"); 
			i = i + 2;
		}	
	}
}

Odd numbers from 1 to 30 using a while loop output

Please Enter any Number : 30
1	3	5	7	9	11	13	15	17	19	21	23	25	27	29

Java Program to Print Odd Numbers from 1 to N using Method

The program of this odd number is the same as the first example. Still, we separated the logic and placed it in a separate method.

import java.util.Scanner;

public class OddNumbers4 {
	private static Scanner sc;
	public static void main(String[] args) 
	{
		int number;
		sc = new Scanner(System.in);
		
		System.out.print(" Please Enter any Number : ");
		number = sc.nextInt();	
		
		findOddNum(number);	
	}
	
	public static void findOddNum(int num)
	{
		int i;
		for(i = 1; i <= num; i++)
		{
			if(i % 2 != 0)
			{
				System.out.print(i +"\t"); 
			}
		}	
	}
}

Odd numbers from 1 to 100 using functions output

Please Enter any Number : 100
1	3	5	7	9	11	13	15	17	19	21	23	25	27	29	31	33	35	37	39	41	43	45	47	49	51	53	55	57	59	61	63	65	67	69	71	73	75	77	79	81	83	85	87	89	91	93	95	97	99

Java Program to Print Odd Numbers between a Given Range

This Java program allows the user to enter Minimum and maximum values. Next, the example returns odd numbers between Minimum value and maximum value.

import java.util.Scanner;

public class Example5 {

	private static Scanner sc;
	public static void main(String[] args) 
	{
		int minimum, maximum;
		sc = new Scanner(System.in);
		
		System.out.print(" Please Enter the Minimum value : ");
		minimum = sc.nextInt();	
		
		System.out.print(" Please Enter the Maximum value : ");
		maximum = sc.nextInt();	
		
		findOddNum(minimum, maximum);	
	}
	
	public static void findOddNum(int minimum, int maximum)
	{
		int i;
		if(minimum % 2 == 0)
		{
			minimum++;
		}
		for(i = minimum; i <= maximum; i++)
		{
			if(i % 2 != 0)
			{
				System.out.print(i +"\t"); 
			}
		}	
	}
}

Odd numbers from 1 to N using for loop output

Please Enter the Minimum value : 5
 Please Enter the Maximum value : 60
5	7	9	11	13	15	17	19	21	23	25	27	29	31	33	35	37	39	41	43	45	47	49	51	53	55	57	59

Please refer to