In this article, we will show you, How to Write a Program for Armstrong Number in C using While Loop, For Loop, Functions and Recursion. Here, we will also show you, C Program for Armstrong Number between 1 to n.
If the given number is equal to the sum of the power of n for each digit present in that integer then, that number can be Armstrong Number in C programming.
For example, 153 is an Armstrong Number in C programming. Number of individual digits in 153 = 3
153 = 1³ + 5³ + 3³
= 1 + 125 + 27 = 153
Below steps will show you the common approach to check for the Armstrong Number in C programming
Steps:
- Enter any number
- Divide the given number into individual digits (For Example, Divide 153 into 1, 5 and 3)
- Calculate the power of n for each individual and add those numbers
- Compare the original value with the Sum value.
- If they exactly matched then it is an Armstrong number. Otherwise, it is not an Armstrong Number in C
C Armstrong Number using While Loop
This program for Armstrong Number in C allows the user to enter any positive integer and then, this program will check whether a number is Armstrong Number or Not using the While Loop
/* Armstrong Number in C using While Loop */
#include <stdio.h>
#include <math.h>
int main()
{
int Number, Temp, Reminder, Times =0, Sum = 0;
printf("\nPlease Enter number to Check for Armstrong \n");
scanf("%d", &Number);
//Helps to prevent altering the original value
Temp = Number;
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}
Temp = Number;
while( Temp > 0)
{
Reminder = Temp %10;
Sum = Sum + pow(Reminder, Times);
Temp = Temp /10;
}
printf("\n Sum of entered number is = %d\n", Sum);
if ( Number == Sum )
printf("\n %d is Armstrong Number.\n", Number);
else
printf("\n %d is not a Armstrong Number.\n", Number);
return 0;
}OUTPUT
ANALYSIS
This Armstrong Number in C program allows the user to enter any positive integer. Next, that number is assigned to variable Number.
Next, We assign the original value to the Temp variable. This will help us to preserve our original value and then do all the manipulation on Temp variable.
Below While loop will make sure that, the given number is greater than 0. Statements inside the while loop will split the numbers and counts the number of individual digits inside the given number.
If you don’t understand the logic, Please refer C Program to Count Number Of Digits in a Number article.
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}Second While loop will make sure that, the given number is greater than 0. Let us see the working principle of this while loop in iteration wise
For this Armstrong number in c demonstration, User Entered value: Number = 1634 and Sum = 0
Temp = Number
Temp = 1634
First Iteration
Reminder = Temp %10
Reminder = 1634 % 10 = 4
Sum = Sum + pow (Reminder, Times)
For this Armstrong Number in C example, Times = 3 because number of digits in 1634 = 4. So pow() function will multiply the Reminder 4 times as shown below
Sum = Sum + (Reminder * Reminder * Reminder * Reminder)
Sum = 0 + (4 * 4 * 4 * 4)
Sum = 0 + 256
Sum = 256
Temp = Temp /10 = 1634 /10
Temp = 163
NOTE: If the number of digits count is 5 then Reminder will be multiplied by 5 times.
Second Iteration
From the first Iteration the values of both Temp and Sum has been changed as: Temp = 163 and Sum = 256
Reminder = Temp %10
Reminder = 163 % 10 = 3
Sum = 256 + (3 * 3 * 3 * 3)
Sum = 256 + 81 => 337
Temp = Temp /10 => 163 /10
Temp = 16
Third Iteration
From the Third Iteration of this C Armstrong Number program, the values of both Temp and Sum has been changed as: Temp = 16 and Sum = 337
Reminder = Temp %10
Reminder = 16 % 10 = 6
Sum = 337 + (6 * 6 * 6 *6) => 337 + 1296
Sum = 1633
Temp = 16 /10
Temp = 1
Fourth Iteration
From the Fourth Iteration the values of both Temp and Sum has been changed as: Temp = 1 and Sum = 1633
Reminder = Temp %10
Reminder = 1 % 10 = 0
Sum = 1633 + (1 * 1 * 1 * 1)
Sum = 1633 + 1 => 1634
Temp = 1/10
Temp = 0
Here Number = 0 so, the while loop condition in this c Armstrong Number program will fail
if ( Number == Sum ) – Condition will check whether the user enter number is exactly equal to Sum number or not. This condition is True, then it is Armstrong else the given number is not Armstrong number.
if ( Number == Sum ) => if(1634 == 1634) –TRUE. So, Number is an Armstrong Number
NOTE: If you are finding the Armstrong number below 1000 then you can simply remove the while loop to count the number of digits in a number and then replace the below code
Sum = Sum + pow(Reminder, Times); With Sum = Sum + (Reminder * Reminder * Reminder)
C Program for Armstrong Number using For Loop
This program for Armstrong number in c allows the user to enter any positive integer and then, this program will check whether a number is Armstrong Number or Not using For Loop
/* Armstrong Number in C using For loop */
#include <stdio.h>
#include <math.h>
int main()
{
int Number, Temp, Reminder, Times =0, Sum = 0;
printf("\nPlease Enter any number to Check for Armstrong \n");
scanf("%d", &Number);
Temp = Number;
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}
for(Temp = Number; Temp > 0; Temp = Temp /10 )
{
Reminder = Temp % 10;
Sum = Sum + pow(Reminder, Times);
}
printf("\nSum of entered number is = %d\n", Sum);
if ( Number == Sum )
printf("\n%d is Armstrong Number.\n", Number);
else
printf("%d is not the Armstrong Number.\n", Number);
return 0
}OUTPUT
We just replaced the While loop in the above Armstrong Number in c example with the For loop. If you don’t understand the for loop then please refer For Loop article here: For Loop in C Programming
Program for Armstrong Number in C using Functions
This C Armstrong Number program allows the user to enter any positive integer. Next, it checks whether the number is Armstrong Number or Not using Functions
/* Armstrong Number in C using Functions*/
#include <stdio.h>
#include <math.h>
int Check_Armstrong (int);
int main()
{
int Number, Sum = 0;
printf("\nPlease Enter any number to Check for Armstrong \n");
scanf("%d", &Number);
Sum = Check_Armstrong (Number);
printf("Sum of entered number is = %d\n", Sum);
if ( Number == Sum )
printf("\n%d is Armstrong Number.\n", Number);
else
printf("%d is not Armstrong Number.\n", Number);
return 0;
}
int Check_Armstrong (int Number)
{
int Temp, Reminder, Times =0, Sum = 0;
Temp = Number;
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}
for(Temp = Number; Temp > 0; Temp = Temp /10 )
{
Reminder = Temp %10;
Sum = Sum + pow(Reminder, Times);
}
return Sum;
}OUTPUT
ANALYSIS
Within this Armstrong Number in c program, when the compiler reaches to
Sum = Check_Armstrong (Number); line in main() program then the compiler will immediately jump to below function:
int Check_Armstrong (int Number)
We already explained LOGIC of this Armstrong Number program in the above example.
NOTE: If we create a function with Void then there is no need to return any value. However, if we declared a function with any data type (int, float etc) then we have return something out from the function.
Armstrong Number in C using Recursion program
This program for Armstrong Number in C allows you to enter any positive integer and then, this program will check whether a number is Armstrong Number or Not using Recursion concept.
/* Armstrong Number in C using Recursion */
#include <stdio.h>
#include <math.h>
int Check_Armstrong (int, int);
int main()
{
int Number, Sum = 0, Times =0,Temp;
printf("\nPlease Enter number to Check for Armstrong \n");
scanf("%d", &Number);
Temp = Number;
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}
Sum = Check_Armstrong (Number, Times);
printf("Sum of entered number is = %d\n", Sum);
if ( Number == Sum )
printf("\n%d is Armstrong Number.\n", Number);
else
printf("%d is not the Armstrong Number.\n", Number);
return 0;
}
int Check_Armstrong (int Number, int Times)
{
static int Reminder, Sum = 0;
if (Number > 0)
{
Reminder = Number %10;
Sum = Sum + pow(Reminder, Times);
Check_Armstrong (Number /10, Times);
return Sum;
}
else
return 0;
}OUTPUT
ANALYSIS
In this Armstrong Number program we used the below statement inside a function,
Armstrong_Check (Number /10);
This statement will help to call the function Recursively with the updated value. If you miss this statement then, after completing the first line it will terminate.
For example, Number = 153 then the output will be 27
Let’s see the If condition of this C Armstrong Number
if (Number > 0) will check whether the number is greater than 0 or not. For Recursive functions it is very important to place a condition before using the function recursively. Otherwise, we will end up in infinite execution (Same like Infinite Loop).
Please be careful :)
Armstrong Numbers in C between 1 to 1000 (or n)
This C Armstrong Number program allows you to enter a minimum and maximum values. This program find Armstrong Numbers between the Minimum and Maximum values.
/* Armstrong Number in C between 1 to n */
#include<stdio.h>
#include <math.h>
int Check_Armstrong (int);
int main()
{
int Number,Reminder,Reverse,Temp, Sum;
int Minimum,Maximum;
printf("\nPlease Enter the Minimum & Maximum Values\n");
scanf("%d %d",&Minimum, &Maximum);
printf("Armstrong Numbers Between %d and %d are:\n",Minimum, Maximum);
for(Number = Minimum; Number <= Maximum; Number++)
{
Sum = Check_Armstrong (Number);
if(Number == Sum)
printf("%d ",Number);
}
return 0;
}
int Check_Armstrong (int Number)
{
int Temp, Reminder, Times =0, Sum = 0;
Temp = Number;
while (Temp != 0)
{
Times = Times + 1;
Temp = Temp / 10;
}
for(Temp = Number; Temp > 0; Temp = Temp /10 )
{
Reminder = Temp %10;
Sum = Sum + pow(Reminder, Times);
}
return Sum;
}OUTPUT
ANALYSIS:
This Armstrong Number in c program allows the user to enter a minimum and maximum values.
for (Number=Minimum; Number<=Maximum; Number++)
This For Loop helps the compiler to iterate between Minimum and Maximum Variables, iteration starts at the Minimum and then it will not exceed Maximum variable.
if(Number==Sum) -– condition will check whether the iteration number is exactly equal to the Reverse number or not. And, if this condition is True, then it is Armstrong else the given number is not Armstrong number.
If this condition is True then, below statement will be printed
printf("%d ",Number);Thank you for Visiting Our Blog
