How to Write a Program for Armstrong Number in C using While Loop, For Loop, Functions, and Recursion.? Here, we will also show you, C Program for Armstrong Number between 1 to n.

If the given number is equal to the sum of the power of n for each digit present in that integer then, that number can be Armstrong Number in C programming.

For example, 153 is an Armstrong Number in C programming. Number of individual digits in 153 = 3

153 = 1³ + 5³ + 3³

= 1 + 125 + 27 = 153

Below steps will show you the common approach to check for the Armstrong Number in C programming**Steps:**

- Enter any number
- Divide the given number into individual digits (For Example, Divide 153 into 1, 5 and 3)
- Calculate the power of n for each individual and add those numbers
- Compare the original value with the Sum value.
- If they exactly matched, then it is an Armstrong number. Otherwise, it is not an Armstrong Number in C

## C Armstrong Number using While Loop

This program for Armstrong Number in C allows the user to enter any positive integer and then, this program will check whether a number is Armstrong Number or Not using the While Loop

/* Armstrong Number in C using While Loop */ #include <stdio.h> #include <math.h> int main() { int Number, Temp, Reminder, Times =0, Sum = 0; printf("\nPlease Enter number to Check for Armstrong \n"); scanf("%d", &Number); //Helps to prevent altering the original value Temp = Number; while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; } Temp = Number; while( Temp > 0) { Reminder = Temp %10; Sum = Sum + pow(Reminder, Times); Temp = Temp /10; } printf("\n Sum of entered number is = %d\n", Sum); if ( Number == Sum ) printf("\n %d is Armstrong Number.\n", Number); else printf("\n %d is not a Armstrong Number.\n", Number); return 0; }

**OUTPUT**

**ANALYSIS**

This Armstrong Number in C program allows the user to enter any positive integer. Next, that number assigned to variable Number.

Next, We assign the original value to the Temp variable. It will help us to preserve our original value and then do all the manipulation on the Temp variable.

Below While loop will make sure that the given number is greater than 0, and the statements inside the while loop will split the numbers and counts the number of individual digits inside the given number.

If you don’t understand the logic, Please refer C Program to Count Number Of Digits in a Number article.

while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; }

Second While loop will make sure that, the given number is greater than 0. Let us see the working principle of this while loop in iteration wise

For this Armstrong number in c demonstration, User Entered value: Number = 1634 and Sum = 0

Temp = Number

Temp = 1634

**First Iteration**

Reminder = Temp %10

Reminder = 1634 % 10 = 4

Sum = Sum + pow (Reminder, Times)

For this Armstrong Number in C example, Times = 3 because of the number of digits in 1634 = 4. So pow() function will multiply the Reminder 4 times as shown below

Sum = Sum + (Reminder * Reminder * Reminder * Reminder)

Sum= 0 + (4 * 4 * 4 * 4) => 0 + 256

Sum = 256

Temp = Temp /10 = 1634 /10

Temp = 163

**NOTE:** If the number of digits count is 5, then Reminder will be multiplied by 5 times.

**Second Iteration**

From the first Iteration, the values of both the Temp and Sum has changed as Temp = 163 and Sum = 256

Reminder = Temp %10

Reminder = 163 % 10 = 3

Sum = 256 + (3 * 3 * 3 * 3)

Sum = 256 + 81 => 337

Temp = Temp /10 => 163 /10

Temp = 16

**Third Iteration**

Temp = 16 and Sum = 337

Reminder = Temp %10

Reminder = 16 % 10 = 6

Sum = 337 + (6 * 6 * 6 *6) => 337 + 1296

Sum = 1633

Temp = 16 /10

Temp = 1

**Fourth Iteration**

Temp = 1 and Sum = 1633

Reminder = Temp %10

Reminder = 1 % 10 = 0

Sum = 1633 + (1 * 1 * 1 * 1)

Sum = 1633 + 1 => 1634

Temp = 1/10

Temp = 0

**Here, **Number = 0. So, the while loop condition in this c Armstrong Number program will fail

if ( Number == Sum ) – Condition will check whether the user enter number is exactly equal to Sum number or not. This condition is True, and it is Armstrong, else the given number is not Armstrong number.

if ( Number == Sum ) => if(1634 == 1634) –TRUE. So, Number is an Armstrong Number

**NOTE: **If you are finding the Armstrong number below 1000, remove the while loop to count the number of digits in a number. Next, replace the below code

Sum = Sum + pow(Reminder, Times); With Sum = Sum + (Reminder * Reminder * Reminder)

## C Program for Armstrong Number using For Loop

This program for Armstrong number in c allows the user to enter any positive integer. And then, this program will check whether a number is Armstrong Number or Not using For Loop

/* Armstrong Number in C using For loop */ #include <stdio.h> #include <math.h> int main() { int Number, Temp, Reminder, Times =0, Sum = 0; printf("\nPlease Enter any number to Check for Armstrong \n"); scanf("%d", &Number); Temp = Number; while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; } for(Temp = Number; Temp > 0; Temp = Temp /10 ) { Reminder = Temp % 10; Sum = Sum + pow(Reminder, Times); } printf("\nSum of entered number is = %d\n", Sum); if ( Number == Sum ) printf("\n%d is Armstrong Number.\n", Number); else printf("%d is not the Armstrong Number.\n", Number); return 0 }

**OUTPUT**

We just replaced the While loop in the above Armstrong Number in c example with the For loop. If you don’t understand the for loop, please refer For Loop article here: For Loop in C Programming

## Program for Armstrong Number in C using Functions

This C Armstrong Number program allows the user to enter any positive integer. Next, it checks whether the number is Armstrong Number or Not using Functions

/* Armstrong Number in C using Functions*/ #include <stdio.h> #include <math.h> int Check_Armstrong (int); int main() { int Number, Sum = 0; printf("\nPlease Enter any number to Check for Armstrong \n"); scanf("%d", &Number); Sum = Check_Armstrong (Number); printf("Sum of entered number is = %d\n", Sum); if ( Number == Sum ) printf("\n%d is Armstrong Number.\n", Number); else printf("%d is not Armstrong Number.\n", Number); return 0; } int Check_Armstrong (int Number) { int Temp, Reminder, Times =0, Sum = 0; Temp = Number; while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; } for(Temp = Number; Temp > 0; Temp = Temp /10 ) { Reminder = Temp %10; Sum = Sum + pow(Reminder, Times); } return Sum; }

**OUTPUT**

**ANALYSIS**

Within this Armstrong Number in c program, when the compiler reaches to

Sum = Check_Armstrong (Number); line in the main() program then the compiler will immediately jump to below function:

int Check_Armstrong (int Number)

We already explained the LOGIC of this Armstrong Number program in the above example.

**NOTE: **If we create a function with Void, then there is no need to return any value. However, if we declared a function with any data type (int, float, etc.), then we have to return something out from the function.

## Armstrong Number in C using Recursion program

This program for Armstrong Number in C allows you to enter any positive integer. Next, this program will check whether a number is Armstrong Number or Not using Recursion concept.

/* Armstrong Number in C using Recursion */ #include <stdio.h> #include <math.h> int Check_Armstrong (int, int); int main() { int Number, Sum = 0, Times =0,Temp; printf("\nPlease Enter number to Check for Armstrong \n"); scanf("%d", &Number); Temp = Number; while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; } Sum = Check_Armstrong (Number, Times); printf("Sum of entered number is = %d\n", Sum); if ( Number == Sum ) printf("\n%d is Armstrong Number.\n", Number); else printf("%d is not the Armstrong Number.\n", Number); return 0; } int Check_Armstrong (int Number, int Times) { static int Reminder, Sum = 0; if (Number > 0) { Reminder = Number %10; Sum = Sum + pow(Reminder, Times); Check_Armstrong (Number /10, Times); return Sum; } else return 0; }

**OUTPUT**

**ANALYSIS**

In this Armstrong Number program, we used the below statement inside a function,

Armstrong_Check (Number /10);

This statement will help to call the function Recursively with the updated value. If you miss this statement, after completing the first line, it will terminate.

For example, Number = 153 then the output will be 27

Let’s see the If condition of this C Armstrong Number

if (Number > 0) will check whether the number is greater than 0 or not. For Recursive functions, it is very important to place a condition before using the function recursively. Otherwise, we will end up in infinite execution (Same like Infinite Loop).

Please be careful :)

## Armstrong Numbers in C between 1 to 1000 (or n)

This C Armstrong Number program allows you to enter a minimum and maximum values. This program finds Armstrong Numbers between the Minimum and Maximum values.

/* Armstrong Number in C between 1 to n */ #include<stdio.h> #include <math.h> int Check_Armstrong (int); int main() { int Number,Reminder,Reverse,Temp, Sum; int Minimum,Maximum; printf("\nPlease Enter the Minimum & Maximum Values\n"); scanf("%d %d",&Minimum, &Maximum); printf("Armstrong Numbers Between %d and %d are:\n",Minimum, Maximum); for(Number = Minimum; Number <= Maximum; Number++) { Sum = Check_Armstrong (Number); if(Number == Sum) printf("%d ",Number); } return 0; } int Check_Armstrong (int Number) { int Temp, Reminder, Times =0, Sum = 0; Temp = Number; while (Temp != 0) { Times = Times + 1; Temp = Temp / 10; } for(Temp = Number; Temp > 0; Temp = Temp /10 ) { Reminder = Temp %10; Sum = Sum + pow(Reminder, Times); } return Sum; }

**OUTPUT**

**ANALYSIS:**

This Armstrong Number in c program allows the user to enter a minimum and maximum values.

for (Number=Minimum; Number<=Maximum; Number++)

The For Loop helps the compiler to iterate between Minimum and Maximum Variables. Iteration starts at the Minimum, and then it will not exceed the Maximum variable.

if(Number==Sum) -– condition will check whether the iteration number is exactly equal to the Reverse number or not. And, if this condition is True, then it is Armstrong else the given number is not Armstrong number.

If this condition is True then, below statement will print

printf("%d ",Number);