In this article we will show you, how to write a C Program to Count Number of Digits in a Number using For Loop, While Loop, Functions and Recursion
C Program to Count Number of Digits in a Number using While Loop
This program allows the user to enter any positive integer and then it will divide the given number into individual digits and count those individual digits using While Loop in C.
CODE
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/* C Program to Count Number of Digits in a Number using While Loop */ #include <stdio.h> int main() { int Number, Reminder, Count=0; printf("\n Please Enter any number\n"); scanf("%d", &Number); while(Number > 0) { Number = Number / 10; Count = Count + 1; } printf("\n Number of Digits in a Given Number = %d", Count); return 0; } |
OUTPUT
ANALYSIS
This program allows the user to enter any positive integer and then, that number is assigned to the Number variable.
Next, Condition in the While loop will make sure that, the given number is greater than 0 (Means Positive integer and greater than 0)
User Entered value: Number = 9875 and Count = 0
First Iteration
Number = Number / 10
Number = 9875 / 10
Number = 987
Count = Count + 1
Count = 0 + 1
Count = 1
Second Iteration
From the first Iteration the values of both Number and Count has been changed as: Number = 987 and Count = 1
Number = Number / 10
Number = 987 / 10
Number = 98
Count = Count + 1
Count = 1 + 1
Count = 2
Third Iteration
From the Third Iteration the values of both Number and Count has been changed as: Number = 98 and Count = 2
Number = Number / 10
Number = 98 / 10
Number = 9
Count = Count + 1
Count = 2 + 1
Count = 3
Fourth Iteration
From the Fourth Iteration the values of both Number and Count has been changed as: Number = 9 and Count = 3
Number = Number / 10
Number = 9 / 10
Number = 0
Count = Count + 1
Count = 3 + 1
Count = 4
Here Number = 0 so, the condition present in the while loop will fail
Last printf statement will print the number of digits present in the given number using the Count variable as output. So,
The output of given variable 9875 is 4
C Program to Count Number of Digits in a Number using For Loop
This program allows the user to enter any positive integer and then it will divide the given number into individual digits and then count those individual digits using For Loop.
CODE
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/* C Program to Count Number of Digits in a Number using For Loop */ #include <stdio.h> int main() { int Number, Reminder, Count; printf("\n Please Enter any number\n"); scanf("%d", &Number); for (Count=0; Number > 0;Number=Number/10) { Count=Count + 1; } printf("\n Number of Digits in a Given Number = %d", Count); return 0; } |
We just replaced the While loop in the above example with the For loop. If you don’t understand the for loop then please refer For Loop article here: For Loop in C Programming
OUTPUT
C Program to Count Number of Digits in a Number Using Functions
This program allows the user to enter any positive integer and then it will divide the given number into individual digits and counting those individual digits using Functions in C.
CODE
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/* C Program to Count Number of Digits in a Number Using Functions */ #include <stdio.h> int Count_Of_Digits (int); int main() { int Number, Count = 0; printf("\n Please Enter any number\n"); scanf("%d", &Number); Count = Count_Of_Digits (Number); printf("\n Number of Digits in a Given Number = %d", Count); return 0; } int Count_Of_Digits (int Number) { int Count; while(Number > 0) { Number = Number / 10; Count = Count + 1; } return Count; } |
OUTPUT
ANALYSIS
When the compiler reaches to Count_Of_Digits (Number) line in main() program then the compiler will immediately jump to below function:
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int Count_Of_Digits (int Number) |
We already explained LOGIC above example. Please refer C Program to Find Count of the Digits of a Given Number using While Loop Analysis section.
Last line ends with return Count Statement.
NOTE: If we create a function with Void then there is no need to return any value but, if we declared a function with any data type (int, float etc) then we have to return something out from the function.
C Program to Count Number of Digits in a Number Using Recursion
This program allows the user to enter any positive integer and then it will divide the given number into individual digits and counting those individual digits using Recursion in C.
CODE
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/* C Program to Count Number of Digits in a Number Using Recursions */ #include <stdio.h> int Count_Of_Digits (int); int main() { int Number, Count = 0; printf("\n Please Enter any number\n"); scanf("%d", &Number); Count = Count_Of_Digits (Number); printf("\n Number of Digits in a Given Number = %d", Count); return 0; } int Count_Of_Digits (int Number) { static int Count =0; if(Number > 0) { Count = Count + 1; Count_Of_Digits (Number / 10); } return Count; } |
OUTPUT
ANALYSIS
In the Count_Of_Digits (int Number) function definition,
Static variable will initialize the value only when the function called first time.
Count_Of_Digits (Number / 10) statement will help to call the function Recursively with updated value. If you miss this statement then, after completing the first line it will terminate. For example,
Number = 1234
Then the output will be 4
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one more condition should be included for digit 0 in recursion code.
if(n==0)
return 1;
because 0 is also considered as a digit,and your code is failing this testcase.
Why we are dividing a number by 10 ? Why not with any other number like 3 or 5 ? Why 10 ?
If we enter a no 10234 result should be 5. But as per the logic of the program, loop will end after the first zero. Therefore program will result 2. This is the limitation