Java Program to Find Second Largest Array Number

Write a Java Program to Find Second Largest Array Number with an example or find the second largest element or item in a given array.

This Java array example allows the user to enter the secLrg_arr size and the items. Next, we use the Else If statement to find the largest and the second largest event in this secLrg_arr.

import java.util.Scanner;

public class Simple {
	private static Scanner sc;
	
	public static void main(String[] args) {
		int Size, i, first, snd, lg_Position = 0;
		
		sc = new Scanner(System.in);		
		System.out.print("\nPlease Enter the SEC LRG size : ");
		Size = sc.nextInt();

		int[] secLrg_arr = new int[Size];
		System.out.format("\nEnter SEC LRG %d elements  : ", Size);
		for(i = 0; i < Size; i++) 
		{
			secLrg_arr[i] = sc.nextInt();
		}
		
		first = snd = Integer.MIN_VALUE;
		
		for(i = 0; i < Size; i++) 
		{
			if(secLrg_arr[i] > first) {
				snd = first;
				first = secLrg_arr[i];
				lg_Position = i;
			}
			else if(secLrg_arr[i] > snd && secLrg_arr[i] < first)
			{
				snd = secLrg_arr[i];
			}
		}
		System.out.format("\nMaximum Value in SEC LRG Array    = %d", first);
		System.out.format("\nMaximum Value Index position  = %d", lg_Position);
		System.out.format("\n\nSecond Largest Item in SEC LRG Array  = %d", snd);
	}
}

Example 2

In this code, we created a separate SecLargElem function to find and return the second largest item in a given array.

package ArrayPrograms;

import java.util.Scanner;

public class Example {
	private static Scanner sc;
	
	public static void main(String[] args) {
		int Sz, i;
		
		sc = new Scanner(System.in);		
		System.out.print("\nPlease Enter the SEC LRG size : ");
		Sz = sc.nextInt();
		
		int[] secLrg_arr = new int[Sz];
		
		System.out.format("\nEnter SEC LRG %d elements  : ", Sz);
		for(i = 0; i < Sz; i++) 
		{
			secLrg_arr[i] = sc.nextInt();
		}		
		SecLargElem(secLrg_arr, Sz);		
	}
	public static void SecLargElem(int[] secLrg_arr, int Sz) {
		
		int i, first, sec, lg_Position = 0;
		
		first = sec = Integer.MIN_VALUE;
		
		for(i = 0; i < Sz; i++) 
		{
			if(secLrg_arr[i] > first) {
				sec = first;
				first = secLrg_arr[i];
				lg_Position = i;
			}
			else if(secLrg_arr[i] > sec && secLrg_arr[i] < first)
			{
				sec = secLrg_arr[i];
			}
		}
		System.out.format("\\nHighest Item in SEC LRG    = %d", first);
		System.out.format("\nIndex position of Highest = %d", lg_Position);
		System.out.format("\n\nSecond Largest Item in SEC LRG  = %d", sec);
	}
}

Please Enter the SEC LRG size : 11

Enter SEC LRG 11 elements  : 10 20 44 77 89 95 200 22 88 250 111

Highest Item in SEC LRG    = 250
Index position of Highest  = 9

Second Largest Item in SEC LRG  = 200