Java Leap Year Program

How to write Java Leap Year Program using If Statement, Nested If Statement, and Else If Statement in Java Programming with example?. Before we get into Java Leap Year Program, Let us see the logic and definition behind the Leap Year

Java Leap year

The normal year contains 365 days, but the leap year contains 366 days. This extra day added to the February month, that is why we get February 29. As per Mathematics, except century years, Years perfectly divisible by four are called Leap years. Century year’s means they end with 00 such as 1200, 1300, 2400, 2500 etc (Obviously they are divisible by 100). For these century years, we have to calculate further to check the Leap year.

  • If the century year is divisible by 400, then that year is a Leap year
  • If the century year is not divisible by 400, then that year is not a Leap year.

Java Leap Year Program using If Statement

This Java program for leap year allows the user to enter any year. Then this Java program will check whether the user entered year is Leap year or not using the If Else statement

// Java Leap Year Program using If Statement

package DatePrograms;

import java.util.Scanner;

public class LeapYearUsingIf {
	private static Scanner sc;

	public static void main(String[] args) {
		int year;
		sc = new Scanner(System.in);
		
		System.out.println("\n Please Enter any year you wish: ");
		year = sc.nextInt();
		
		if (( year%400 == 0)|| (( year%4 == 0 ) &&( year%100 != 0))) {
			System.out.format("\n %d is a Leap Year. \n", year);
		}
		else {
			System.out.format("\n %d is NOT a Leap Year. \n", year);
		}
	}
}
Java Leap Year Program using If Statement

Let us check for a normal year (Not Leap Year)

 Please Enter any year you wish: 
2015

2015 is NOT a Leap Year.

In this Java leap year program, Since we have to check multiple conditions within one If Statement, we used Logical AND and Logical OR operators. Let us divide the condition to understand it better

1: ( year % 400 == 0)||

2: ( year % 4 == 0 ) &&

3: ( year % 100 != 0))

The first condition (year%400 == 0) will check whether the (year%400) reminder is precisely equal to 0 or not. As per the algorithm, any number that is divisible by 400 is a Leap year.

OR

The second Java If Else statement condition holds two statements, so they both have to be TRUE.

  • The first condition (year%4 == 0) will check whether the remainder of the (year % 4) is exactly equal to 0 or not. If the condition is False, then it will exit from the condition because there is no point in checking the other condition. It is not the Leap year. AND
  • The second condition will check (year % 100) reminder is not equal to 0. If it is TRUE, then the given number is not a century number.
  • Any number that is divisible by four but not by 100, then that number is Leap Year.

TIP: Please refer to Java Logical Operators to understand the Logical And and Logical Or in Java.

Java Leap Year Program using Else If Statement

This Java leap year program allows the user to enter any year. Then the Java program will check whether the user entered year is Leap year or not using the Java Else If statement.

// Java Leap Year Program using Else If Statement

package DatePrograms;

import java.util.Scanner;

public class LeapYearUsingElseIf {
	private static Scanner sc;

	public static void main(String[] args) {
		int year;
		sc = new Scanner(System.in);
		
		System.out.println("\n Please Enter any year you wish: ");
		year = sc.nextInt();
		
		if ( year % 400 == 0) {
			System.out.format("\n %d is a Leap Year. \n", year);
		}
		else if (year%100 == 0) {
			System.out.format("\n %d is NOT a Leap Year. \n", year);
		}
		else if(year%4 == 0) {
			System.out.format("\n %d is a Leap Year. \n", year);
		}
		else {
			System.out.format("\n %d is NOT a Leap Year. \n", year);
		}
	}
}

Java Leap Year output

Please Enter any year you wish: 
1200

1200 is a Leap Year.

In this Java leap year program, the following statements ask the user to enter any year to check whether that year is Leap year or Not. Next, we are going to assign the user entered value to year variable

System.out.println("\n Please Enter any year you wish: ");
year = sc.nextInt();
  • The first If condition will check whether the (year % 400) reminder is exactly equal to 0. As per the algorithm, any number that is divisible by 400 is a Leap year. If this condition Fails, then it will go to the next condition.
  • The second If condition will check (year % 100) reminder is exactly equal to 0 or not. As per the algorithm, any number that is not divisible by 400 but by 100 is Not a Leap year (Century Year). We checked (year % 400) in the First If statement. Because it failed, so it came to the second condition. If both the first and second condition Fails, then it will go to the third condition.
  • The third condition will check whether year mod 4 is equal to 0. If this condition is True, then given year is Leap year because We already checked for the century years in the previous condition. If all the statements Fail, then it will go the Else statement at the end.
  • If all the above statements fail, then it is not a Leap year in Java.

Java Leap Year Program using Nested If Statement

This leap year program in Java helps the user to enter any year. Then the Java program will check whether the user entered year is Leap year or not using the Nested If in Java

// Java Leap Year Program using Nested If Statement
package DatePrograms;

import java.util.Scanner;

public class LeapYearUsingNestedIf {
	private static Scanner sc;

	public static void main(String[] args) {
		int year;
		sc = new Scanner(System.in);
		
		System.out.println("\n Please Enter any year you wish: ");
		year = sc.nextInt();
		
		if ( year % 4 == 0) {
			if (year%100 == 0) {
				if(year%400 == 0) {
					System.out.format("\n %d is a Leap Year. \n", year);
				}
				else {
					System.out.format("\n %d is NOT a Leap Year. \n", year);
				}
			}
			else {
				System.out.format("\n %d is a Leap Year. \n", year);
			}
		}
		else {
			System.out.format("\n %d is NOT a Leap Year. \n", year);
		}
	}
}

Checking Leap year using Nested If output

Please Enter any year you wish: 
2072

2072 is a Leap Year.

In this Java leap year program, the User will enter any year to check whether that year is Leap year or Not. The first If condition will check whether the remainder of the (year%4) is precisely equal to 0 or not.

  • If the condition is False, then the given number is not the Leap year.
  • If the condition is True, then we have check further for the century year. So the Javac compiler will go to the Nested If condition.

The second If condition will check (year%100) reminder is exactly equal to 0 or Not.

  • If this condition is False, then the year is not a century year. So the given number is a Leap year.
  • If the condition is True, then we have check whether the number is divisible by 400 or not. So the Javac compiler will goto to another Nested If condition.

In this condition, the Javac will check whether the remainder of the (year%400) is exactly equal to 0 or not.

  • If the condition is False, then the given number is not the Leap year.
  • If the condition is True, then the given number is Leap Year in java

Java Leap Year Program using Oops

This program for java leap year allows entering any positive integer (year). Then the Java program checks whether the given year is a leap year or not. In this example, we are dividing the code using the Object-Oriented Programming.

To do this, first, we will create a class that holds a method to reverse an integer recursively.

package DatePrograms;

public class LeapYear {
	public int CheckLeapYear(int year) {
		if (( year%400 == 0)|| (( year%4 == 0 ) && ( year%100 != 0))) {
			return year;
		}
		else {
			return 0;
		}
	}
}

Within the Main program of the leap year program in java, we will create an instance of the above-specified class and call the methods.

package DatePrograms;
import java.util.Scanner;
public class LeapYearUsingClass {
	private static Scanner sc;
	public static void main(String[] args) {
		int year, leap;
		sc = new Scanner(System.in);
		System.out.println(" Please Enter any year you wish: ");
		year = sc.nextInt();
		
		LeapYear ly = new LeapYear();
		leap = ly.CheckLeapYear(year);
		
		if(leap != 0) {
			System.out.format("\n %d is a Leap Year. \n", year);
		}
		else {
			System.out.format("\n %d is NOT a Leap Year. \n", year);
		}
	}
}

Leap year program using OOPs output

Please Enter any year you wish: 
2032

2032 is a Leap Year.

LeapYear Class Analysis:

In this java leap year program, first, we declared an integer function CheckLeapYear with one argument. Within the function, we used the If statement to check whether the given year is a leap year or Not and if it is true, then it will return year. Otherwise, it returns zero. We already explained the Logic in the above example.

Main Class Analysis:

First, we created an instance / created an Object of the LeapYear Class

LeapYear ly = new LeapYear();

Next, we are calling the CheckLeapYear method.

leap = ly.CheckLeapYear(year);

Lastly, System.out.println statement will print the output.