Python Program to Print A Star Pattern

This article shows how to write a Python program to print the Alphabet A star pattern using the for loop, while loop, and functions with an example. 

The below alphabet A star pattern example accepts the user-entered rows, and the nested for loop iterates the rows. The If else condition is to print stars at a few positions, get the Alphabet A pattern of stars, and skip others.

rows = int(input("Enter Alphabet A of Stars Rows = "))

for i in range(rows):
    for j in range(rows // 2 + 1):
        if (i == 0 and j != 0 and j != rows // 2) or i == rows // 2 or (j == 0 or j == rows // 2) and i != 0:
            print('*', end='')
        else:
            print(end=' ')
    print()

Enter Alphabet A of Stars Rows = 9
 *** 
*   *
*   *
*   *
*****
*   *
*   *
*   *
*   *

The above example looks good; however, we must modify the program slightly to get the perfect Alphabet A star pattern.

rows = int(input("Enter Alphabet A of Stars Rows = "))
print("====The Alphabet A Star Pattern====")

n = rows

for i in range(rows):
    for j in range(2 * rows):
        if j == n or j == ((2 * rows) - n) or (i == (rows // 2) and n < j < ((2 * rows) - n)):
            print('*', end='')
        else:
            print(end=' ')
    print()
    n = n - 1

Python Program to print the Alphabet A Star pattern using a while loop

Instead of a For loop, this program uses the while loop to iterate the A pattern rows and prints the stars at each position. For more Star Pattern programs >> Click Here.

rows = int(input("Enter Alphabet A of Stars Rows = "))

n = rows
i = 0

while i < rows:
    j = 0
    while j < 2 * rows:
        if j == n or j == ((2 * rows) - n) or (i == (rows // 2) and n < j < ((2 * rows) - n)):
            print('*', end='')
        else:
            print(end=' ')
        j = j + 1
    print()
    i = i + 1
    n = n - 1

Enter Alphabet A of Stars Rows = 10
          *         
         * *        
        *   *       
       *     *      
      *       *     
     ***********    
    *           *   
   *             *  
  *               * 
 *                 *

In this example, we created an APattern function that accepts the rows and the symbol or character to print the Alphabet A pattern of the given symbol.

def APattern(rows, ch):
    n = rows
    for i in range(rows):
        for j in range(2 * rows):
            if j == n or j == ((2 * rows) - n) or (i == (rows // 2) and n < j < ((2 * rows) - n)):
                print('%c' %ch, end='')
            else:
                print(end=' ')
        print()
        n = n - 1


row = int(input("Enter Alphabet A of Stars Rows = "))
sym = input("Symbol for A Pattern = ")
APattern(row, sym)

Enter Alphabet A of Stars Rows = 9
Symbol for A Pattern = $
         $        
        $ $       
       $   $      
      $     $     
     $$$$$$$$$    
    $         $   
   $           $  
  $             $ 
 $               $