Python Program to calculate Sum of Series 1³+2³+3³+….+n³

Write a Python Program to calculate Sum of Series 1³+2³+3³+….+n³ using For Loop and Functions with an example.

The Mathematical formula for Python Sum of series 1³+2³+3³+….+n³ = ( n (n+1) / 6)²

Python Program to calculate Sum of Series 1³+2³+3³+….+n³

This Python program allows users to enter any positive integer. Next, the Python finds the sum of series 1³+2³+3³+….+n³ using the above formula.

# Python Program to calculate Sum of Series 1³+2³+3³+….+n³
import math 

number = int(input("Please Enter any Positive Number  : "))
total = 0

total = math.pow((number * (number + 1)) /2, 2)

print("The Sum of Series upto {0}  = {1}".format(number, total))

Python Sum of Series 1³+2³+3³+….+n³ using math pow output

Please Enter any Positive Number  : 7
The Sum of Series upto 7  = 784.0

Sum = pow (((Number * (Number + 1)) / 2), 2)
= pow (((7 * (7 + 1)) / 2), 2)
Sum = pow (((7 * 8) / 2), 2) = 784

Python Program to calculate Sum of Series 1³+2³+3³+….+n³ Example 2

If you want the Python to display the Series 1³+2³+3³+….+n³ order, we have to add extra For Loop along with If Else.

# Python Program to calculate Sum of Series 1³+2³+3³+….+n³
import math 

number = int(input("Please Enter any Positive Number  : "))
total = 0

total = math.pow((number * (number + 1)) /2, 2)

for i in range(1, number + 1):
    if(i != number):
        print("%d^3 + " %i, end = ' ')
    else:
        print("{0}^3 = {1}".format(i, total))

Python Sum of Series 1³+2³+3³+….+n³ output

Please Enter any Positive Number  : 5
1^3 +  2^3 +  3^3 +  4^3 +  5^3 = 225.0

Python Program to calculate Sum of Series 1³+2³+3³+….+n³ using Functions

This Python Sum of Series 1³+2³+3³+….+n³ program is the same as above. However, in this Python program, we are defining a function to place logic.

# Python Program to calculate Sum of Series 1³+2³+3³+….+n³
import math 

def sum_of_cubes_series(number):
    total = 0

    total = math.pow((number * (number + 1)) /2, 2)

    for i in range(1, number + 1):
        if(i != number):
            print("%d^3 + " %i, end = ' ')
        else:
            print("{0}^3 = {1}".format(i, total))

num = int(input("Please Enter any Positive Number  : "))
sum_of_cubes_series(num)
Please Enter any Positive Number  : 7
1^3 +  2^3 +  3^3 +  4^3 +  5^3 +  6^3 +  7^3 = 784.0

Python Program to find Sum of Series 1³+2³+3³+….+n³ using Recursion

Here, we are using the Python Recursive function to find the Sum of Series 1³+2³+3³+….+n³.

# Python Program to calculate Sum of Series 1³+2³+3³+….+n³

def sum_of_cubes_series(number):
    if(number == 0):
        return 0
    else:
        return (number * number * number) + sum_of_cubes_series(number - 1)

num = int(input("Please Enter any Positive Number  : "))
total = sum_of_cubes_series(num)

print("The Sum of Series upto {0}  = {1}".format(num, total))
Python Program to calculate Sum of Series 1³+2³+3³+….+n³ 4