C++ Program to find Sum of Odd Numbers

Write a C++ Program to find the sum of odd numbers from 0 to n. This C++ program allows you to enter the maximum odd number. Next, we used the for loop (for(number = 1; number <= maximum; number++)) to iterate numbers from 1 to maximum. We used the If condition (if ( number % 2 != 0 ) ) within the loop to check whether the number % 2 not equals 0. If true, add that odd number to the sum value, and print it as the odd number. Next, it prints the sum of the odd numbers as a result.

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Odd Numbers Maximum Limit  =  ";
	cin >> maximum;	
	
	cout <<"\n\nOdd Numbers between 0 and " << maximum << " = ";
	for(number = 1; number <= maximum; number++)
	{
  		if ( number % 2 != 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Odd Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}

C++ Program to find Sum of Odd Numbers Example 2

In this C++ program to calculate the sum of odd Numbers, we altered the for loop (for(number = 1; number <= maximum; number = number + 2)) to remove the If condition. As you can see, we incremented the number by 2 (instead of 1 number++). As we know, every number starts from 1 with an increment of 2 (1 + 2 = 3) will be an odd number. So, we add that odd number to the sum and print the sum as a result.

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Odd Numbers Maximum Limit  =  ";
	cin >> maximum;	
	
	cout <<"\n\nOdd Numbers between 0 and " << maximum << " = ";
	for(number = 1; number <= maximum; number = number + 2)
	{
		sum = sum + number;
		cout << number << " ";
	}
	
	cout << "\nThe Sum of All Odd Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}

Output

Please Enter the Odd Numbers Maximum Limit  =  20

Odd Numbers between 0 and 20 = 1 3 5 7 9 11 13 15 17 19 
The Sum of All Odd Numbers upto 20 = 100

This C++ sum of odd numbers example allows the user to enter the minimum and maximum value. Next, it will calculate the sum of odd numbers from minimum to maximum.

#include<iostream>
using namespace std;

int main()
{
	int number, minimum, maximum, sum = 0;
	
	cout << "\nPlease Enter the Odd Numbers Minimum Limit  =  ";
	cin >> minimum;	
	
	cout << "Please Enter the Odd Numbers Maximum Limit  =  ";
	cin >> maximum;	
	
	cout <<"\nOdd Numbers between " << minimum << " and " << maximum << " = ";
	for(number = minimum; number <= maximum; number++)
	{
  		if ( number % 2 != 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Odd Numbers from " << minimum << " to " << maximum << " = " << sum;
	
 	return 0;
}

Output

Please Enter the Odd Numbers Minimum Limit  =  50
Please Enter the Odd Numbers Maximum Limit  =  70

Odd Numbers between 50 and 70 = 51 53 55 57 59 61 63 65 67 69 
The Sum of All Odd Numbers from 50 to 70 = 600