C# Bitwise Operators

The C# Bitwise operators only applied on numbers. Before these operators work on the given input(number), the system converts that number from decimal to binary. And then, the C# bitwise operator performs its action on bits(binary). And then finally, the result is displayed for us in decimal form after converting bits into decimal.

Input(decimal) ->(decimal to binary) -> bitwise operators perform the necessary action on bits -> Bits converted to decimal -> result is displayed in decimal form.

Let us see the truth table for these C# bitwise operators.

C# Bitwise Operators Example

The following example shows you the working functionality of all the bitwise operators.

using System;
 
class Bitwise_Operators
{
   static void Main()
   {
     int x = 16;
     int y = 10;
     int result;
 
     result = ~x;
     Console.WriteLine("~{0} is {1}", x, result);
 
     result = x & y;
     Console.WriteLine("{0} & {1} = {2}", x, y, result);

     result = x | y;
     Console.WriteLine("{0} | {1} = {2}", x, y, result);
 

     result = x ^ y;
     Console.WriteLine("{0} ^ {1} = {2}", x, y, result);
   }
}

OUTPUT

ANALYSIS

x = 16 and y = 10

The C# Bitwise operations performed as follows:

First, 16 and 10 are converted into bits.

The binary form of 16 is 10000, and 10 is 1010.

~(16) is –17, which is the two’s complement of 16.

10000 & 01010 is 00000
The result is 0

10000 | 01010 is 11010
The decimal form of 11010 is 26 

10000 ^ 01010 is 11010
The decimal form of 11010 is 26

C# Shift Operators

The C# Bitwise Shift operators move bit positions. It means bit positions of the left operand are shifted to either left or right, number of positions specified in the right operand. C# enables a bit shifting with the right shift (>>) and left shift (<<) operators.

Let us see an example of C# code using these Bitwise shift operators.

C# Bitwise Left and Right Shift Operators Example

using System;
 
 class Shift_Operators
 {
     static void Main()
     {
         int x = 16;
         int result;
 
         result = x >> 3;
         Console.WriteLine("{0} >> 3 is {1}", x, result);
 
         result = x << 2;
         Console.WriteLine("{0} << 2 is {1}", x, result);
     }
 }

OUTPUT

ANALYSIS

In the above code

16 >> 3, The binary form of 16 is 0001 0000

10000 is shifted three digits towards the right, i.e., 0000 0010, whose decimal value is 2.

16 << 2,  After shifting binary form of 16, i.e., 0001 0000 by 2 digits towards left, the result is 0100 0000, whose decimal form is 64.