C++ program to Print Even Numbers

Write a C++ Program to Print Even Numbers from 0 to given value. This C++ program allows you to enter any integer number. Next, we used the for loop to iterate numbers from 1 to that number. Within the loop, we used the If statement to check whether i % 2 equal to 0. If true, print the i value as the even number.

#include<iostream>
using namespace std;

int main()
{
	int number;
	
	cout << "\nPlease Enter Maximum limit Value to print Even Numbers =  ";
	cin >> number;
	
	cout << "\nList of Even Numbers from 1 to " << number << " are\n"; 
	for(int i = 1; i <= number; i++)
  	{
  		if ( i % 2 == 0 )
  		{
  			cout << i <<" ";
		}	
  	}
		
 	return 0;
}

OUTPUT

In this C++ Program, we alter the for loop (for(int i = 2; i <= number; i= i + 2)) to remove the If statement to return even Numbers. Here, we incremented the i value to 2 (instead of 1). So that every number from 2 with an increment of two will be an even number.

#include<iostream>
using namespace std;

int main()
{
	int number;
	
	cout << "\nPlease Enter Maximum limit Value to print Even Numbers =  ";
	cin >> number;
	
	cout << "\nList of Even Numbers from 1 to " << number << " are\n"; 
	for(int i = 2; i <= number; i= i + 2)
  	{
  		cout << i <<" ";
  	}
		
 	return 0;
}

OUTPUT

C++ Program to Print Even Numbers using a While Loop

#include<iostream>
using namespace std;

int main()
{
	int number, i = 2;
	
	cout << "\nPlease Enter Maximum limit Value to print Even Numbers =  ";
	cin >> number;
	
	cout << "\nList of Even Numbers from 1 to " << number << " are\n"; 
	while(i <= number)
  	{
  		cout << i <<" ";
  		i = i + 2;
  	}
		
 	return 0;
}

OUTPUT

This C++ print even numbers example allows us to enter a minimum and maximum value. Next, it prints even numbers from minimum to maximum.

#include<iostream>
using namespace std;

int main()
{
	int minimum, maximum;
	
	cout << "\nPlease Enter Minimum limit Value to print Even Numbers =  ";
	cin >> minimum;
	
	cout << "\nPlease Enter Maximum limit Value to print Even Numbers =  ";
	cin >> maximum;
	
	cout << "\nList of Even Numbers from " << minimum << " to " << maximum << " are\n"; 
	for(int i = minimum; i <= maximum; i++)
  	{
  		if ( i % 2 == 0 )
  		{
  			cout << i <<" ";
		}	
  	}
		
 	return 0;
}

RESULT

The first if statement in this C++ print even numbers check whether the minimum value percentage 2 is not equal to 0. If True, it is an odd number, so increment the minimum value by 1; otherwise, enter into the for loop.

#include<iostream>
using namespace std;

int main()
{
	int minimum, maximum;
	
	cout << "\nPlease Enter Minimum limit Value to print Even Numbers =  ";
	cin >> minimum;
	
	cout << "\nPlease Enter Maximum limit Value to print Even Numbers =  ";
	cin >> maximum;
	
	if (minimum % 2 != 0 ) 
    {
    	minimum++;
    }
    
	cout << "\nList of Even Numbers from " << minimum << " to " << maximum << " are\n"; 
	for(int i = minimum; i <= maximum; i = i + 2)
  	{
  		cout << i <<" ";	
  	}
		
 	return 0;
}

RESULT