C++ Program to find Sum of Even Numbers

Write a C++ Program to find the sum of even numbers from 0 to n. This C++ program allows you to enter the maximum number. Next, we used the for loop (for(number = 1; number <= maximum; number++)) to iterate numbers from 1 to maximum. We used the If condition within the loop to check whether the number % 2 equals to 0. If true, add that number to the sum value (sum = sum + number;), and print the number value as the even number.

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\nEven Numbers between 0 and " << maximum << " = ";
	for(number = 1; number <= maximum; number++)
	{
  		if ( number % 2 == 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}
Please Enter the Maximum Limit for Even Numbers  =  20

Even Numbers between 0 and 20 = 2 4 6 8 10 12 14 16 18 20 
The Sum of All Even Numbers upto 20 = 110

C++ Program to find the sum of even Numbers Example 2

In this C++ program to calculate the sum of even Numbers, we altered the for loop (for(number = 2; number <= maximum; number = number + 2)) to remove the If statement. As you can see, we incremented the number to 2 (instead of 1 number++). As we know, every number starts from 2 with an increment of 2 will be an even number. So, we add that number to the sum and print the sum as a result.

#include<iostream>
using namespace std;

int main()
{
	int number, maximum, sum = 0;
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\nEven Numbers between 0 and " << maximum << " = ";
	for(number = 2; number <= maximum; number = number + 2)
	{		
		sum = sum + number;
		cout << number << " ";
	}
	
	cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum;
	
 	return 0;
}
Please Enter the Maximum Limit for Even Numbers  =  30

Even Numbers between 0 and 30 = 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30 
The Sum of All Even Numbers upto 30 = 240

This C++ program to find the sum of even numbers allows the user to enter the minimum and maximum values. Next, it will calculate the sum of even numbers from the minimum to the maximum.

#include<iostream>
using namespace std;

int main()
{
	int number, minimum, maximum, sum = 0;
	
	cout << "\nPlease Enter the Minimum Limit for Even Numbers  =  ";
	cin >> minimum;	
	
	cout << "\nPlease Enter the Maximum Limit for Even Numbers  =  ";
	cin >> maximum;	
	
	cout <<"\n\nEven Numbers between  " << minimum << " and " << maximum << " = ";
	for(number = minimum; number <= maximum; number++)
	{		
		if ( number % 2 == 0 ) 
		{
  			cout << number << " ";
			sum = sum + number;
		}
	}
	
	cout << "\nThe Sum of All Even Numbers from " << minimum << " to " << maximum << " = " << sum;
	
 	return 0;
}
C++ Program to find Sum of Even Numbers

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