Write a C++ Program to find the sum of even numbers from 0 to n. This C++ program allows you to enter the maximum number. Next, we used the for loop (for(number = 1; number <= maximum; number++)) to iterate numbers from 1 to maximum. We used the If condition within the loop to check whether the number % 2 equals to 0. If true, add that number to the sum value (sum = sum + number;), and print the number value as the even number.

#include<iostream> using namespace std; int main() { int number, maximum, sum = 0; cout << "\nPlease Enter the Maximum Limit for Even Numbers = "; cin >> maximum; cout <<"\nEven Numbers between 0 and " << maximum << " = "; for(number = 1; number <= maximum; number++) { if ( number % 2 == 0 ) { cout << number << " "; sum = sum + number; } } cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum; return 0; }

```
Please Enter the Maximum Limit for Even Numbers = 20
Even Numbers between 0 and 20 = 2 4 6 8 10 12 14 16 18 20
The Sum of All Even Numbers upto 20 = 110
```

## C++ Program to find the sum of even Numbers Example 2

In this C++ program to calculate the sum of even Numbers, we altered the for loop (for(number = 2; number <= maximum; number = number + 2)) to remove the If statement. As you can see, we incremented the number to 2 (instead of 1 number++). As we know, every number starts from 2 with an increment of 2 will be an even number. So, we add that number to the sum and print the sum as a result.

#include<iostream> using namespace std; int main() { int number, maximum, sum = 0; cout << "\nPlease Enter the Maximum Limit for Even Numbers = "; cin >> maximum; cout <<"\nEven Numbers between 0 and " << maximum << " = "; for(number = 2; number <= maximum; number = number + 2) { sum = sum + number; cout << number << " "; } cout << "\nThe Sum of All Even Numbers upto " << maximum << " = " << sum; return 0; }

```
Please Enter the Maximum Limit for Even Numbers = 30
Even Numbers between 0 and 30 = 2 4 6 8 10 12 14 16 18 20 22 24 26 28 30
The Sum of All Even Numbers upto 30 = 240
```

This C++ sum of even numbers example allows the user to enter the minimum and maximum value. Next, it will calculate the sum of even numbers from minimum to maximum.

#include<iostream> using namespace std; int main() { int number, minimum, maximum, sum = 0; cout << "\nPlease Enter the Minimum Limit for Even Numbers = "; cin >> minimum; cout << "\nPlease Enter the Maximum Limit for Even Numbers = "; cin >> maximum; cout <<"\n\nEven Numbers between " << minimum << " and " << maximum << " = "; for(number = minimum; number <= maximum; number++) { if ( number % 2 == 0 ) { cout << number << " "; sum = sum + number; } } cout << "\nThe Sum of All Even Numbers from " << minimum << " to " << maximum << " = " << sum; return 0; }