C++ Program to Check Number is Palindrome

Write a C++ Program to Check Number is Palindrome with an example. Any number can be palindrome if the reverse of that number equal to the actual number. For instance, 121 is a palindrome because when you reverse it, you get the same number. 

In this C++ palindrome number example, we assigned the actual value to temp. Next, we revered that temp value. I suggest you refer to the Reverse a Number article. Finally, we used the If condition to check whether the number equal to reverse and print the palindrome.

include<iostream>

using namespace std;

int main()
{
	int number, temp, reminder, reverse = 0;
	
	cout << "Please Enter the Number to Check Palindrome or Not =  ";
	cin >> number;
	
	temp = number;
	
	while (temp > 0)
	{
    	reminder = temp % 10;
    	reverse = reverse * 10 + reminder;
    	temp = temp / 10;
	}
	cout << "\nReverse of given Number = " << reverse << "\n\n";
	
	if(number == reverse) {
		cout << number << " is a Palindrome Number";
	}	
	else {
		cout << number << " is Not a Palindrome Number";
	}
 	return 0;
}

OUTPUT

Let me check with the palindrome number.

C++ Program to Check Number is Palindrome using For Loop

#include<iostream>

using namespace std;

int main()
{
	int number, temp, reminder, reverse = 0;
	
	cout << "Please Enter the Number to Check Palindrome or Not =  ";
	cin >> number;
	
	for(temp = number; temp > 0; temp = temp / 10)
	{
    	reminder = temp % 10;
    	reverse = reverse * 10 + reminder;    	
	}
	cout << "\nReverse of given Number = " << reverse << "\n\n";
	
	if(number == reverse) {
		cout << number << " is a Palindrome Number";
	}	
	else {
		cout << number << " is Not a Palindrome Number";
	}
 	return 0;
}

OUTPUT

C++ program to find Palindrome number using Functions

#include<iostream>

using namespace std;

int reverseNumbers(int number)
{
	int reminder, reverse = 0;
	
	for(; number > 0; number = number / 10)
	{
    	reminder = number % 10;
    	reverse = reverse * 10 + reminder;    	
	}
	return reverse;
}
int main()
{
	int number, reverse = 0;
	
	cout << "Please Enter the Number to Check Palindrome or Not =  ";
	cin >> number;
	
	reverse = reverseNumbers(number);
	cout << "\nReverse of given Number = " << reverse << "\n\n";
	
	if(number == reverse) {
		cout << number << " is a Palindrome Number";
	}	
	else {
		cout << number << " is Not a Palindrome Number";
	}
 	return 0;
}

OUTPUT

C++ Program to find Number is Palindrome using Recursion

In this C++ code, int reverseNumbers(int number) method reverse the given number. Here, reverseNumbers(number / 10) line recursively calls the int reverseNumbers(int number) method with updated value.

In this C++ code, int reverseNumbers(int number) method reverse the given number. Here, reverseNumbers(number / 10) line recursively calls the int reverseNumbers(int number) method with updated value.
#include<iostream>

using namespace std;

int reverseNumbers(int number)
{
	static int reminder, reverse = 0;
	
	if(number > 0)
	{
    	reminder = number % 10;
    	reverse = reverse * 10 + reminder;
    	reverseNumbers(number / 10);
    	return reverse;
	}
	else
		return 0;
	
}
int main()
{
	int number, reverse = 0;
	
	cout << "Please Enter the Number to Check Palindrome or Not =  ";
	cin >> number;
	
	reverse = reverseNumbers(number);
	cout << "\nReverse of given Number = " << reverse << "\n\n";
	
	if(number == reverse) {
		cout << number << " is a Palindrome Number";
	}	
	else {
		cout << number << " is Not a Palindrome Number";
	}
 	return 0;
}

RESULT

C++ Program to Print Palindrome Numbers from 1 to 100

This C++ palindrome number example allows the user to enter the minimum and maximum values. Next, it prints the palindrome numbers between min and max values.

#include<iostream>
using namespace std;

int main()
{
	int minimum, maximum, number, temp, reminder, reverse;
	
	cout << "\nPlease Enter the Minimum Value =  ";
	cin >> minimum;
	
	cout << "\nPlease Enter the Maximum Value =  ";
	cin >> maximum;
	
	cout << "\nPalindrome Numbers between " << minimum << " and " << maximum << " = ";
	for(number = minimum; number <= maximum; number++ )
	{
		temp = number;
		reverse = 0;
		
		while (temp > 0)
		{
			reminder = temp % 10;
			reverse = reverse * 10 + reminder;
			temp = temp / 10;
		}
		if(number == reverse) {
			cout << number << "  ";
		}
	}
 	return 0;
}

RESULT