C++ Program to Calculate Sum of Series 1³+2³+3³+n³

Write a C++ Program to Calculate Sum of Series 1³+2³+3³+n³ with an example. The math formula to find Sum of Series 1³+2³+3³+……+n³ = (n(n + 1)/6)². 

#include<iostream>
#include<cmath>
using namespace std;

int main()
{
	int number, sum = 0;
	
	cout << "Enter the Number to find sum of Series 1^3 + 2^3 =  ";
	cin >> number;
	
	sum = pow(((number * (number + 1)) / 2), 2);
	 	
	cout << "\nThe Sum of the Series 1^3 + 2^3 + .. upto " << number << " = " << sum << "\n\n";

 	return 0;
}

OUTPUT

The below shown C++ Program to Calculate Sum of Series 1³+2³+3³+n³ is the same as the above. Here, we used C++ for loop to display the 1³+2³+3³+n³ series as an output.

#include<iostream>
#include<cmath>
using namespace std;

int main()
{
	int number, sum = 0;
	
	cout << "Enter the Number to find sum of Series 1^3 + 2^3 =  ";
	cin >> number;
	
	sum = pow(((number * (number + 1)) / 2), 2);
	 	
	cout << "\nThe Sum of the Series 1^3 + 2^3 + .. upto " << number << " = " << sum << "\n\n";
	
	for(int i = 1; i <= number; i++)
	{
		if (i != number)
			cout << i << "^3 + ";
		else
			cout << i << "^3 = " << sum;
	}

 	return 0;
}

OUTPUT

C++ Program to Calculate Sum of Series 1³+2³+3³+n³ using Functions

#include<iostream>
#include<cmath>
using namespace std;

void sumOf13Series (int number)
{
	int sum = 0;
	
	sum = pow(((number * (number + 1)) / 2), 2);
	 	
	cout << "\nThe Sum of the Series 1^3 + 2^3 + .. upto " << number << " = " << sum << "\n\n";
	
	for(int i = 1; i <= number; i++)
	{
		if (i != number)
			cout << i << "^3 + ";
		else
			cout << i << "^3 = " << sum;
	}
}
int main()
{
	int number;
	
	cout << "Enter the Number to find sum of Series 1^3 + 2^3 =  ";
	cin >> number;
	
	sumOf13Series (number);

 	return 0;
}

RESULT